Description
You are playing the Bulls and Cows game with your friend.
You write down a secret number and ask your friend to guess what the number is. When your friend makes a guess, you provide a hint with the following info:
- The number of “bulls”, which are digits in the guess that are in the correct position.
- The number of “cows”, which are digits in the guess that are in your secret number but are located in the wrong position. Specifically, the non-bull digits in the guess that could be rearranged such that they become bulls.
Given the secret number secret
and your friend’s guess guess
, return the hint for your friend’s guess.
The hint should be formatted as "xAyB"
, where x
is the number of bulls and y
is the number of cows. Note that both secret
and guess
may contain duplicate digits.
Example 1:
Input: secret = “1807”, guess = “7810” Output: “1A3B” Explanation: Bulls are connected with a ’|’ and cows are underlined: “1807” | “7810”
Example 2:
Input: secret = “1123”, guess = “0111” Output: “1A1B” Explanation: Bulls are connected with a ’|’ and cows are underlined: “1123” “1123” | or | “0111” “0111” Note that only one of the two unmatched 1s is counted as a cow since the non-bull digits can only be rearranged to allow one 1 to be a bull.
Constraints:
1 <= secret.length, guess.length <= 1000
secret.length == guess.length
secret
andguess
consist of digits only.
Code
class Solution {
public:
string getHint(string secret, string guess) {
if (secret.size() != guess.size() || secret.empty()) { return "0A0B"; }
int bulls = 0;
int cows = 0;
vector<int> sMap(10, 0), gMap(10, 0);
for(int i = 0; i < secret.length(); i++) {
if(secret[i] == guess[i]) bulls++;
else {
++sMap[secret[i] - '0'];
++gMap[guess[i] - '0'];
}
}
for(int i = 0; i < 10; i++) {
cows += min(sMap[i], gMap[i]);
}
string hint = to_string(bulls) + "A" + to_string(cows) + "B";
return hint;
}
};