Description
Given a string s
consisting only of characters 'a'
, 'b'
, and 'c'
. You are asked to apply the following algorithm on the string any number of times:
- Pick a non-empty prefix from the string
s
where all the characters in the prefix are equal. - Pick a non-empty suffix from the string
s
where all the characters in this suffix are equal. - The prefix and the suffix should not intersect at any index.
- The characters from the prefix and suffix must be the same.
- Delete both the prefix and the suffix.
Return the minimum length of s
after performing the above operation any number of times (possibly zero times).
Example 1:
Input: s = “ca” Output: 2 Explanation: You can’t remove any characters, so the string stays as is.
Example 2:
Input: s = “cabaabac” Output: 0 Explanation: An optimal sequence of operations is:
- Take prefix = “c” and suffix = “c” and remove them, s = “abaaba”.
- Take prefix = “a” and suffix = “a” and remove them, s = “baab”.
- Take prefix = “b” and suffix = “b” and remove them, s = “aa”.
- Take prefix = “a” and suffix = “a” and remove them, s = "".
Example 3:
Input: s = “aabccabba” Output: 3 Explanation: An optimal sequence of operations is:
- Take prefix = “aa” and suffix = “a” and remove them, s = “bccabb”.
- Take prefix = “b” and suffix = “bb” and remove them, s = “cca”.
Constraints:
1 <= s.length <= 105
s
only consists of characters'a'
,'b'
, and'c'
.
Code
Time Complexity: , Space Complexity:
注意 edge case,當左右指標移動到中間時,會有兩種 case:
- cbc
- caac
兩種的差別在於左指標是否和他移動過來之前的位置相等。