Description

Given two arrays arr1 and arr2, the elements of arr2 are distinct, and all elements in arr2 are also in arr1.

Sort the elements of arr1 such that the relative ordering of items in arr1 are the same as in arr2. Elements that do not appear in arr2 should be placed at the end of arr1 in ascending order.

Example 1:

Input: arr1 = [2,3,1,3,2,4,6,7,9,2,19], arr2 = [2,1,4,3,9,6] Output: [2,2,2,1,4,3,3,9,6,7,19]

Example 2:

Input: arr1 = [28,6,22,8,44,17], arr2 = [22,28,8,6] Output: [22,28,8,6,17,44]

Constraints:

  • 1 <= arr1.length, arr2.length <= 1000
  • 0 <= arr1[i], arr2[i] <= 1000
  • All the elements of arr2 are distinct.
  • Each arr2[i] is in arr1.

Code

Time Complexity: , Space Complexity:

class Solution {
public:
    vector<int> relativeSortArray(vector<int>& arr1, vector<int>& arr2) {
        unordered_map<int, int> mp;
        for(int i = 0; i < arr2.size(); i++)
            mp[arr2[i]] = i;
        auto cmp = [&](const int& n1, const int& n2){
            if(mp.find(n1) != mp.end() && mp.find(n2) != mp.end())
                return mp[n1] < mp[n2];
            else {
                if(mp.find(n1) == mp.end() && mp.find(n2) != mp.end()) {
                    return false;
                } else if(mp.find(n1) != mp.end() && mp.find(n2) == mp.end()) {
                    return true;
                } else {
                    return n1 < n2;
                }
            }
        };
 
        sort(arr1.begin(), arr1.end(), cmp);
        return arr1;
    }
};

使用 map 是因為不在 arr2 中的 arr1 元素需要 sort in ascending order。

class Solution {
public:
    vector<int> relativeSortArray(vector<int>& arr1, vector<int>& arr2) {
        map<int, int> mp;
        for(auto a: arr1) {
            mp[a]++;
        }
 
        int index = 0;
        for(auto a: arr2) {
            while(mp[a] > 0) {
                arr1[index++] = a;
                mp[a]--;
            }
        }
 
        for(auto m: mp) {
            while(m.second-- > 0)
                arr1[index++] = m.first; 
        }
 
        return arr1;
        
    }
};
 
 

Source