Description
Given two integers n
and k
, return all possible combinations of k
numbers chosen from the range [1, n]
.
You may return the answer in any order.
Example 1:
Input: n = 4, k = 2 Output: [[1,2],[1,3],[1,4],[2,3],[2,4],[3,4]] Explanation: There are 4 choose 2 = 6 total combinations. Note that combinations are unordered, i.e., [1,2] and [2,1] are considered to be the same combination.
Example 2:
Input: n = 1, k = 1 Output: 1 Explanation: There is 1 choose 1 = 1 total combination.
Constraints:
1 <= n <= 20
1 <= k <= n
Code
介於 Subsets 和 Permutations 之間(以所求的 set size 的而言)。
class Solution {
public:
vector<vector<int>> combine(int n, int k) {
vector<vector<int>> answer;
vector<int> curr;
vector<int> nums;
for(int i = 1; i <= n; i++) {
nums.push_back(i);
}
helper(answer, nums, 0, curr, k);
return answer;
}
void helper(vector<vector<int>> &answer, vector<int> nums, int index, vector<int> curr, int k) {
if(curr.size() == k) {
answer.push_back(curr);
return;
}
for(int i = index; i < nums.size(); i++) {
curr.push_back(nums[i]);
// backtracking
helper(answer, nums, i + 1, curr, k);
curr.pop_back();
}
}
};