Description
Given the root
of a binary search tree and an integer k
, return true
if there exist two elements in the BST such that their sum is equal to k
, or false
otherwise.
Example 1:
Input: root = [5,3,6,2,4,null,7], k = 9 Output: true
Example 2:
Input: root = [5,3,6,2,4,null,7], k = 28 Output: false
Constraints:
- The number of nodes in the tree is in the range
[1, 104]
. -104 <= Node.val <= 104
root
is guaranteed to be a valid binary search tree.-105 <= k <= 105
Code
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
bool findTarget(TreeNode* root, int k) {
set<int> m;
return helper(root, m, k);
}
bool helper(TreeNode* node, set<int>& map, int target) {
if(!node) return false;
if(map.count(target - node->val) > 0) return true;
map.insert(node->val);
return helper(node->left, map, target) || helper(node->right, map, target);
}
};