Description

Given a binary array nums, return the maximum length of a contiguous subarray with an equal number of 0 and 1.

Example 1:

Input: nums = [0,1] Output: 2 Explanation: [0, 1] is the longest contiguous subarray with an equal number of 0 and 1.

Example 2:

Input: nums = [0,1,0] Output: 2 Explanation: [0, 1] (or [1, 0]) is a longest contiguous subarray with equal number of 0 and 1.

Constraints:

  • 1 <= nums.length <= 105
  • nums[i] is either 0 or 1.

Code

class Solution {
public:
    int findMaxLength(vector<int>& nums) {
 
        unordered_map<int, int> mp;
        mp[0] = -1; 
 
        int sum = 0, maxLen = 0;
        for(int i = 0; i < nums.size(); i++) {
            sum += nums[i] == 1 ? 1 : -1;
            if(mp.count(sum)) maxLen = max(maxLen, i - mp[sum]);
            else mp[sum] = i;
        }
 
        return maxLen;
    }
};

Source