Description
Implement the RandomizedSet
class:
RandomizedSet()
Initializes theRandomizedSet
object.bool insert(int val)
Inserts an itemval
into the set if not present. Returnstrue
if the item was not present,false
otherwise.bool remove(int val)
Removes an itemval
from the set if present. Returnstrue
if the item was present,false
otherwise.int getRandom()
Returns a random element from the current set of elements (it’s guaranteed that at least one element exists when this method is called). Each element must have the same probability of being returned.
You must implement the functions of the class such that each function works in average O(1)
time complexity.
Example 1:
Input [“RandomizedSet”, “insert”, “remove”, “insert”, “getRandom”, “remove”, “insert”, “getRandom”] [[], [1], [2], [2], [], [1], [2], []] Output [null, true, false, true, 2, true, false, 2]
Explanation RandomizedSet randomizedSet = new RandomizedSet(); randomizedSet.insert(1); // Inserts 1 to the set. Returns true as 1 was inserted successfully. randomizedSet.remove(2); // Returns false as 2 does not exist in the set. randomizedSet.insert(2); // Inserts 2 to the set, returns true. Set now contains [1,2]. randomizedSet.getRandom(); // getRandom() should return either 1 or 2 randomly. randomizedSet.remove(1); // Removes 1 from the set, returns true. Set now contains [2]. randomizedSet.insert(2); // 2 was already in the set, so return false. randomizedSet.getRandom(); // Since 2 is the only number in the set, getRandom() will always return 2.
Constraints:
-231 <= val <= 231 - 1
- At most
2 *
105
calls will be made toinsert
,remove
, andgetRandom
. - There will be at least one element in the data structure when
getRandom
is called.
Code
Time Complexity: , Space Complexity:
重點在於,要刪除時,換到最後面再刪除才會是 。