Description

Given an array of integers temperatures represents the daily temperatures, return an array answer such that answer[i] is the number of days you have to wait after the ith day to get a warmer temperature. If there is no future day for which this is possible, keep answer[i] == 0 instead.

Example 1:

Input: temperatures = [73,74,75,71,69,72,76,73] Output: [1,1,4,2,1,1,0,0]

Example 2:

Input: temperatures = [30,40,50,60] Output: [1,1,1,0]

Example 3:

Input: temperatures = [30,60,90] Output: [1,1,0]

Constraints:

  • 1 <= temperatures.length <= 105
  • 30 <= temperatures[i] <= 100

Code

Monotonic Stack

解題邏輯和 Next Greater Element I 一樣。

Time Complexity: , Space Complexity:

class Solution {
public:
    vector<int> dailyTemperatures(vector<int>& temperatures) {
        stack<int> st;
        int n = temperatures.size();
        vector<int> res(n, 0);
        for(int i = n - 1; i >= 0; i--) {
            // maitain decreasing order of stack
            while(!st.empty() && temperatures[st.top()] <= temperatures[i]) {
                st.pop();
            }
 
            if(!st.empty()) {
                res[i] = st.top() - i;
            }
            st.push(i);
        }
        return res;
    }
};

Source