Description
Given an array of integers temperatures
represents the daily temperatures, return an array answer
such that answer[i]
is the number of days you have to wait after the ith
day to get a warmer temperature. If there is no future day for which this is possible, keep answer[i] == 0
instead.
Example 1:
Input: temperatures = [73,74,75,71,69,72,76,73] Output: [1,1,4,2,1,1,0,0]
Example 2:
Input: temperatures = [30,40,50,60] Output: [1,1,1,0]
Example 3:
Input: temperatures = [30,60,90] Output: [1,1,0]
Constraints:
1 <= temperatures.length <= 105
30 <= temperatures[i] <= 100
Code
Monotonic Stack
解題邏輯和 Next Greater Element I 一樣。
Time Complexity: , Space Complexity:
class Solution {
public:
vector<int> dailyTemperatures(vector<int>& temperatures) {
stack<int> st;
int n = temperatures.size();
vector<int> res(n, 0);
for(int i = n - 1; i >= 0; i--) {
// maitain decreasing order of stack
while(!st.empty() && temperatures[st.top()] <= temperatures[i]) {
st.pop();
}
if(!st.empty()) {
res[i] = st.top() - i;
}
st.push(i);
}
return res;
}
};