Given two strings s
and t
, determine if they are isomorphic.
Two strings s
and t
are isomorphic if the characters in s
can be replaced to get t
.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character, but a character may map to itself.
Example 1:
Input: s = “egg”, t = “add” Output: true
Example 2:
Input: s = “foo”, t = “bar” Output: false
Example 3:
Input: s = “paper”, t = “title” Output: true
Constraints:
1 <= s.length <= 5 * 104
t.length == s.length
s
andt
consist of any valid ascii character.
Code
其實就是 Word Pattern,code 直接複製貼上稍微改一下就 AC了。
class Solution {
public:
bool isIsomorphic(string s, string t) {
if(s.size() != t.size()) return false;
unordered_map<char, int> pti;
unordered_map<char, int> sti;
for(int i = 0; i < s.size(); i++) {
if(pti[s[i]] != sti[t[i]]) return false;
// default is 0 if key not exist!
pti[s[i]] = i + 1;
sti[t[i]] = i + 1;
}
return true;
}
};