Description
You are climbing a staircase. It takes n
steps to reach the top.
Each time you can either climb 1
or 2
steps. In how many distinct ways can you climb to the top?
Example 1:
Input: n = 2 Output: 2 Explanation: There are two ways to climb to the top.
- 1 step + 1 step
- 2 steps
Example 2:
Input: n = 3 Output: 3 Explanation: There are three ways to climb to the top.
- 1 step + 1 step + 1 step
- 1 step + 2 steps
- 2 steps + 1 step
Constraints:
1 <= n <= 45
Code
其實就是 Fibonacci Number。
Time Complexity: , Space Complexity:
class Solution {
public:
int climbStairs(int n) {
if (n <= 2) return n;
int n1 = 1;
int n2 = 2;
int ways;
for(int i = 3; i <= n; i++) {
ways = n1 + n2;
n1 = n2;
n2 = ways;
}
return ways;
}
};
Fibonacci computing hack: a = (b += a) - a;
class Solution {
public:
int climbStairs(int n) {
int a = 1, b = 1;
while (n--)
a = (b += a) - a;
return a;
}
};