Description
Given the roots of two binary trees root
and subRoot
, return true
if there is a subtree of root
with the same structure and node values of subRoot
and false
otherwise.
A subtree of a binary tree tree
is a tree that consists of a node in tree
and all of this node’s descendants. The tree tree
could also be considered as a subtree of itself.
Example 1:
Input: root = [3,4,5,1,2], subRoot = [4,1,2] Output: true
Example 2:
Input: root = [3,4,5,1,2,null,null,null,null,0], subRoot = [4,1,2] Output: false
Constraints:
- The number of nodes in the
root
tree is in the range[1, 2000]
. - The number of nodes in the
subRoot
tree is in the range[1, 1000]
. -104 <= root.val <= 104
-104 <= subRoot.val <= 104
Code
有用到 Same Tree 當作輔助。
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
bool isSubtree(TreeNode* root, TreeNode* subRoot) {
if(!root) return false;
if(isSameTree(root, subRoot)) return true;
return isSubtree(root->left, subRoot) || isSubtree(root->right, subRoot);
}
bool isSameTree(TreeNode* node1, TreeNode* node2) {
if(!node1 && !node2) return true;
if(!node1 || !node2) return false;
return node1->val == node2->val && isSameTree(node1->left, node2->left) && isSameTree(node1->right, node2->right);
}
};