Description
Given an input string s
, reverse the order of the words.
A word is defined as a sequence of non-space characters. The words in s
will be separated by at least one space.
Return a string of the words in reverse order concatenated by a single space.
Note that s
may contain leading or trailing spaces or multiple spaces between two words. The returned string should only have a single space separating the words. Do not include any extra spaces.
Example 1:
Input: s = “the sky is blue” Output: “blue is sky the”
Example 2:
Input: s = ” hello world ” Output: “world hello” Explanation: Your reversed string should not contain leading or trailing spaces.
Example 3:
Input: s = “a good example” Output: “example good a” Explanation: You need to reduce multiple spaces between two words to a single space in the reversed string.
Constraints:
1 <= s.length <= 104
s
contains English letters (upper-case and lower-case), digits, and spaces' '
.- There is at least one word in
s
.
Follow-up: If the string data type is mutable in your language, can you solve it in-place with O(1)
extra space?
Code
Time Complexity: , Space Complexity:
class Solution {
public:
string reverseWords(string s) {
int i = 0, j = 0, n = s.length();
int wordCount = 0;
while(j < n) {
while(j < n && s[j] == ' ') j++;
if(j == n) break;
if(wordCount) s[i++] = ' ';
int l = i;
while(j < n && s[j] != ' ') {
s[i++] = s[j++];
}
if(i > l) {
reverse(s.begin() + l, s.begin() + i);
wordCount++;
}
}
s = s.substr(0, i);
reverse(s.begin(), s.end());
return s;
}
};